it’s like the electric field is inversely proportional to the applied surface area of the enclosing surface area. The flux through a closed (Gaussian) surface depends on the net charge enclosed by the surface, according to Gauss’s law. The shape and size of the surface does not change the flux.

## Why is the electric flux through a closed surface with a given enclosed charge is independent of the size or shape of the surface?

The **electric flux** is **independent of the size** and **shape** of the **closed surface** that contains the **charge** because all the **field** lines from the **enclosed charge** pas **through** the **surface**.

## Why is the flux through a closed surface always zero?

The flux of a vector field through a closed surface is always zero **if there is no source or sink of the vector field in the volume enclosed by the surface**. … The flux of a electric field through a closed surface is always zero if there is no net charge in the volume enclosed by the surface.

## Why does electric flux does not depend on area?

Along the other four sides, the direction of the **area** vector **is** perpendicular to the direction of the **electric field**. Therefore, the scalar product of the **electric field** with the **area** vector **is** zero, giving zero **flux**.

## Does electric flux depend on charge distribution?

Gauss’s law of electricity, which is included within the fundamental laws of electromagnetism, states that the electric flux through a closed surface with electric charge inside, **just depends on the net charge enclosed in the surface** and does not depend the shape or size of the surface.

## What does it mean if the electric flux through a closed surface is negative?

**Field lines directed into a closed surface** are considered negative; those directed out of a closed surface are positive. If there is no net charge within a closed surface, every field line directed into the surface continues through the interior and is directed outward elsewhere on the surface.

## What will be the flux through a closed surface which does not contain any charge?

Therefore, if a closed surface does not have any charges inside the enclosed volume, then the electric flux through the surface **is zero**.

## Can a free charge Cannot be present inside a closed surface?

Nope! There is a theorem called Gauss’ theorem, which states that the flux of across a **surface** , is proportional to the amount of net **charge inside** the volume **enclosed** by .

## Is electric flux through a closed surface zero?

2. The net electric flux through any closed surface surrounding a net charge ‘q’ is independent of the shape of the surface. 3. The net **electric flux is zero through** any closed surface surrounding a zero net charge.

## What is the flux through a closed surface?

So if you have a sphere(closed surface) and you put it in an uniform electric field, then the total flux is 0. However, the Gauss’s law states that the electric field flux through a closed surface **equals the enclosed charge divided by the permitivity of free space.**

## Does electric flux increase as area increases?

The electric flux through a closed surface (see Gauss’s Law ), such as a sphere, is independent of **area** because as the closed surface becomes larger the electric field will become weaker but applied over a larger area, but the resulting electric flux will be the same as the electric flux through a smaller closed …

## Is electric flux dependent on shape?

As per the Guess theorem in electrostatics, **electric flux does not depend on the shape** or size of the surface. The electric flux depends only on the charge enclosed by the surface.

## What is the reason why increasing the area of a closed surface does not affect the total flux?

it’s like the electric field is inversely proportional to the applied surface area of the enclosing surface area. The flux through a closed (Gaussian) surface depends on the net charge enclosed by the surface, according to Gauss’s law. **The shape and size of the surface does not change the flux**.