Question: Why does electric flux through a closed surface only depend on the net enclosed charge not its position?

it’s like the electric field is inversely proportional to the applied surface area of the enclosing surface area. The flux through a closed (Gaussian) surface depends on the net charge enclosed by the surface, according to Gauss’s law. The shape and size of the surface does not change the flux.

Why is the electric flux through a closed surface with a given enclosed charge is independent of the size or shape of the surface?

The electric flux is independent of the size and shape of the closed surface that contains the charge because all the field lines from the enclosed charge pas through the surface.

Why is the flux through a closed surface always zero?

The flux of a vector field through a closed surface is always zero if there is no source or sink of the vector field in the volume enclosed by the surface. … The flux of a electric field through a closed surface is always zero if there is no net charge in the volume enclosed by the surface.

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Why does electric flux does not depend on area?

Along the other four sides, the direction of the area vector is perpendicular to the direction of the electric field. Therefore, the scalar product of the electric field with the area vector is zero, giving zero flux.

Does electric flux depend on charge distribution?

Gauss’s law of electricity, which is included within the fundamental laws of electromagnetism, states that the electric flux through a closed surface with electric charge inside, just depends on the net charge enclosed in the surface and does not depend the shape or size of the surface.

What does it mean if the electric flux through a closed surface is negative?

Field lines directed into a closed surface are considered negative; those directed out of a closed surface are positive. If there is no net charge within a closed surface, every field line directed into the surface continues through the interior and is directed outward elsewhere on the surface.

What will be the flux through a closed surface which does not contain any charge?

Therefore, if a closed surface does not have any charges inside the enclosed volume, then the electric flux through the surface is zero.

Can a free charge Cannot be present inside a closed surface?

Nope! There is a theorem called Gauss’ theorem, which states that the flux of across a surface , is proportional to the amount of net charge inside the volume enclosed by .

Is electric flux through a closed surface zero?

2. The net electric flux through any closed surface surrounding a net charge ‘q’ is independent of the shape of the surface. 3. The net electric flux is zero through any closed surface surrounding a zero net charge.

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What is the flux through a closed surface?

So if you have a sphere(closed surface) and you put it in an uniform electric field, then the total flux is 0. However, the Gauss’s law states that the electric field flux through a closed surface equals the enclosed charge divided by the permitivity of free space.

Does electric flux increase as area increases?

The electric flux through a closed surface (see Gauss’s Law ), such as a sphere, is independent of area because as the closed surface becomes larger the electric field will become weaker but applied over a larger area, but the resulting electric flux will be the same as the electric flux through a smaller closed …

Is electric flux dependent on shape?

As per the Guess theorem in electrostatics, electric flux does not depend on the shape or size of the surface. The electric flux depends only on the charge enclosed by the surface.

What is the reason why increasing the area of a closed surface does not affect the total flux?

it’s like the electric field is inversely proportional to the applied surface area of the enclosing surface area. The flux through a closed (Gaussian) surface depends on the net charge enclosed by the surface, according to Gauss’s law. The shape and size of the surface does not change the flux.

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